3^2x-1=7^x+1

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Solution for 3^2x-1=7^x+1 equation: 



3^2x-1=7^x+1

We move all terms to the left:

3^2x-1-(7^x+1)=0

We get rid of parentheses

3^2x-7^x-1-1=0

We add all the numbers together, and all the variables

3^2x-7^x-2=0

We move all terms containing x to the left, all other terms to the right

3^2x-7^x=2

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